Two elastic balls with masses of 200 g and 100 g are suspended side by side so that their

Two elastic balls with masses of 200 g and 100 g are suspended side by side so that their centers are at the same level. The first ball is deflected so that it rises to a height of 18 cm and is released. How high will each of the balls rise after impact?

When the ball is raised to a height, potential energy appears in it:
E = mgh,
where m is the mass of the ball,
g – acceleration of gravity,
h is the height of the rise.
Let us find the potential energy of the ball, if its mass is 200 g, and the height of rise is 18 cm:
E = 0.2 * 9.8 * 0.18 = 0.35 J.
When the ball is at its lowest point, all potential energy is completely converted into kinetic energy.
If we take into account that the balls are absolutely elastic and all the energy of the first ball is completely transferred to the second ball, then we can determine the height of the rise of the second ball:
h = 0.35 / (0.1 * 9.8) = 0.36 m.
Answer: the second ball will rise 36 cm.