Two electric bulbs with a resistance of 200 and 240 ohms are connected in series to a network with a voltage of 220 V
| February 23, 2021 | education
Two electric bulbs with a resistance of 200 and 240 ohms are connected in series to a network with a voltage of 220 V. What is the current strength in each lamp?
When the conductors are connected in series, the current passing through the conductors will be the same.
Determine the resistance of the series conductors.
R = R1 + R2 = 200 + 240 = 440 ohms.
According to Ohm’s law, we determine the strength of the current passing through the conductors.
I = U / R = 220/440 = 0.5 A.
Answer: The amperage on both lamps is 0.5 A.
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