# Two forces act on the body, one in the direction of movement and equal to 20N, and the other

**Two forces act on the body, one in the direction of movement and equal to 20N, and the other perpendicular to the direction of movement and equal to 10N. while the body moved 10m. what work is done in this case?**

Given:

F1 = 20 N;

F2 = 10 N;

S = 10 m.

Find: A.

Decision:

Let’s write the formula for finding the work in terms of the cosine.

A = FScosa.

However, it cannot be used in a standard way, since the condition gives two forces that act on the body. It should also be borne in mind that one of these forces acts at an angle of 90.

Therefore, we write the formula of work in a different way: A = (F1 + F2) S.

We know the cosine of 90 degrees is zero. Therefore, further the formula will look like this: A = F1S

Substitute the values into it and get the answer: A = 20 * 10 = 200 J.

Answer: 200