Two forces of 2 N and 3 N are applied to one point of the body. The angle between the vectors of these

Two forces of 2 N and 3 N are applied to one point of the body. The angle between the vectors of these forces is 90 °. Which acceleration does a body with a mass of 720 g acquire?

According to Newton’s second law:

F = m * a, where F is the resultant force (N), m is the mass of the body (m = 720 g = 0.72 kg), and is the desired acceleration of the body.

Since F1 and F2 are directed at an angle of 90º to each other, we calculate the resultant force by the Pythagorean theorem:

F² = F1² + F2², where F1 = 2 N, F2 = 3 N.

F = sqrt (F1² + F2²) = sqrt (2² + 3²) = sqrt (4 + 9) = sqrt (13) = 3.6 N.

Body Acceleration:

a = F / m = 3.6 / 0.72 = 5 m / s².

Answer: The body will acquire an acceleration of 5 m / s².