Two groups of lamps are connected in parallel to a network with a voltage of 220 V. In one group there

| April 11, 2021 | education

Two groups of lamps are connected in parallel to a network with a voltage of 220 V. In one group there are eight lamps with a resistance of 160 ohms each, and in the other ten lamps with a resistance of 200 ohms each. Determine impedance and total amperage.

Let’s determine the resistance of the section of the circuit with a series connection of eight lamps with a resistance of 160 ohms.

R1 = 8 * 160 = 1280 Om.

Let’s determine the resistance of a section of a circuit with a series connection of ten lamps with a resistance of 200 ohms.

R2 = 10 * 200 = 2000 Om.

Determine the total resistance of the circuit when the sections of the circuit are connected in parallel.

Rrev = R1 * R2 / (R1 + R2) = 1280 * 2000 / (1280 + 2000) = 2560000/3280 = 32000/41 = 780.5 Om.

According to Ohm’s law, we determine the current strength in an unbranched section of the circuit.

I = U / Rob = 220 / 780.5 = 0.28 A.

Answer: The total resistance is 780.5 ohms, the current is 0.28 A.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.