Two identical glasses with H2SO4 were placed on the scales. One added 62 g. Al. How much Zn

Two identical glasses with H2SO4 were placed on the scales. One added 62 g. Al. Question: How much Zn must be added to another glass to level the scales again?

Given:
m (Al) = 62 g

To find:
m (Zn) -?

1) Write the reaction equations:
3H2SO4 + 2Al => Al2 (SO4) 3 + 3H2 ↑;
H2SO4 + Zn => ZnSO4 + H2 ↑;
2) Calculate the amount of Al substance:
n (Al) = m (Al) / M (Al) = 62/27 = 2.3 mol;
3) Determine the amount of substance H2:
n1 (H2) = n (Al) * 3/2 = 2.3 * 3/2 = 3.5 mol;
n2 (H2) = n1 (H2) = 3.5 mol;
4) Determine the amount of Zn substance:
n (Zn) = n2 (H2) = 3.5 mol;
5) Calculate the mass of Zn:
m (Zn) = n (Zn) * M (Zn) = 3.5 * 65 = 228 g.

Answer: The mass of Zn is 228 g.