Two identical metal balls are located at some distance from each other, interact with a force of 0.25 N.
Two identical metal balls are located at some distance from each other, interact with a force of 0.25 N. Determine the distance between the balls if the charge of one of them is +1 μC, and the second is -4 μC.
Given: F (force of interaction) = 0.25 N; q1 (charge of the first ball) = 1 μC (1 * 10 ^ 6-6 C); q2 (charge of the second ball) = -4 μC (-4 * 10 ^ -6 C); we will assume that the balls are in air.
Constants: k (proportionality coefficient) = 9 * 10 ^ 9 N * m2 / Cl2.
The distance between the balls can be expressed from the formula (Coulomb’s law): F = k * | q1 | * | q2 | / r ^ 2, whence r = √ (k * | q1 | * | q2 | / F).
Calculation: r = √ (9 * 10 ^ 9 * 1 * 10 ^ -6 * 4 * 10 ^ -6 / 0.25) ≈ 0.38 m.
Answer: The distance between the balls is 38 cm.