Two identical small-sized conducting balls are located in the air; their discharges are 4.0 * 10 at minus

| August 14, 2021 | education

Two identical small-sized conducting balls are located in the air; their discharges are 4.0 * 10 at minus 7 and 0.80 * 10 at minus 7C. The strength of their interaction is 0.8 * 10 in minus 3N Determine the distance between them.

To find the distance between these conducting balls, we use the formula: F = k * | q2 | * | q1 | / (r ^ 2 * ε), whence we express: r = √ (k * | q ^ 2 | * | q1 | / (F * ε)).

Constants: k – coeff. proportionality (k = 9 * 10 ^ 9 N * m2 / Cl2); ε is the dielectric constant of the medium (the conducting balls are in the air and ε = 1).

Variables: | q ^ 2 | – modulus of charge of the second conducting ball (| q ^ 2 | = 0.8 * 10 ^ -7 C); | q1 | – modulus of charge of the first conducting ball (| q1 | = 4 * 10 ^ -7 C); F is the force of interaction (F = 0.8 * 10 ^ -3 N).

Calculation: r = √ (k * | q2 | * | q1 | / (F * ε)) = √ (9 * 10 ^ 9 * 0.8 * 10 ^ -7 * 4 * 10 ^ -7 / (0, 8 * 10 ^ -3 * 1)) = 0.6 m.

Answer: The distance between these conducting balls is 0.6 m.



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