Two identical weights are suspended on a string thrown over the block. when overloads are put

Two identical weights are suspended on a string thrown over the block. when overloads are put on one of them, it begins to move uniformly accelerated and within 3 seconds travels a path of 45 cm.determine the acceleration of the weights and their speed at the end of the path

Given:

t = 3 seconds – time interval;

L = 45 centimeters = 0.45 meters – the path that the weights pass during the time interval t.

It is required to determine the acceleration of the weights a (m / s ^ 2) and their speed at the end of the path v (m / s).

According to the condition of the problem, the weights were initially in equilibrium, that is, their speed was equal to zero. Then:

L = a * t ^ 2/2, hence:

a = 2 * L / t ^ 2 = 2 * 0.45 / 3 ^ 2 = 0.9 / 9 = 0.1 m / s ^ 2.

Then, the speed of movement of the weights at the end of the section of the path will be equal to:

v = a * t = 3 * 0.1 = 0.3 m / s.

Answer: the acceleration of the weights is 0.1 m / s ^ 2, their speed at the end of the path is 0.3 m / s.