Two identical wooden blocks float in water and kerosene. Compare the Archimedean forces acting on the bars.

Given:

ro1 = 1000 kg / m3 (kilogram per cubic meter) – density of water (clean);

ro2 = 800 kg / m3 is the density of kerosene;

g = 9.8 N / kg (Newton per kilogram) – acceleration of gravity;

V1 = V2 = V – the volume of both bars is the same.

It is required to compare F1 and F1 – Archimedean (buoyancy) forces acting on the bars when they are immersed in water and in kerosene.

When immersed in water, the buoyancy force will be equal to:

F1 = ro1 * g * V = 1000 * 9.8 * V = 9800 * V.

When immersed in kerosene, the buoyancy force will be equal to:

F2 = ro2 * g * V = 800 * 9.8 * V = 7840 * V.

It can be seen that F1> F2 (9800 * V> 7840 * V) at 9800 * V / (7840 * V) = 1.25 times.

Answer: a bar immersed in water will be affected by 1.25 times the Archimedean force.