Two inclined ones are drawn from point to plane. Find the lengths of the inclined ones if one of them is 7 cm
Two inclined ones are drawn from point to plane. Find the lengths of the inclined ones if one of them is 7 cm larger than the other, and the projection of the inclined ones is 6 cm and 15 cm.
Let us express the length of the first oblique, for which we use the variable a.
Then, according to the condition of the assignment, the length of the second can be represented as (7 + a.)
Since we know from the condition that they are drawn from one point, that is, they have a common perpendicular, as well as the lengths of their projections, then it is possible to draw up an equation and find out what these oblique ones are equal to:
a ^ 2 – 6 ^ 2 = (7 + a) ^ 2 – 15 ^ 2;
a ^ 2 – 36 = 49 + 14a + a ^ 2 – 225;
14a = 140;
a = 10;
7 + 10 = 17.
Answer: The first slope is 10 cm, and the second is 17 cm.