Two inelastic balls weighing 6 kg and 4 kg move at speeds of 8 m / s and 3 m / s

| May 22, 2021 | education

Two inelastic balls weighing 6 kg and 4 kg move at speeds of 8 m / s and 3 m / s towards each other. How fast will they move after a completely inelastic impact?

Given:

m1 = 6 kilograms is the mass of the first ball;

v1 = 8 m / s – the speed of the first ball;

m2 = 4 kilograms – the mass of the second ball;

v2 = 3 m / s – the speed of the second ball.

It is required to determine the speed of the balls v (m / s) after an absolutely inelastic impact.

After a completely inelastic impact, both balls will move together as one. Then, given that initially the balls moved towards each other:

m1 * v1 – m2 * v2 = (m1 + m2) * v;

v = (m1 * v1 – m2 * v2) / (m1 + m2) = (6 * 8 – 4 * 3) / (6 + 4) =

= (48 – 12) / 10 = 36/10 = 3.6 m / s.

Answer: the balls will move at a speed of 3.6 m / s.



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