Two lead balls with masses m1 = 100g and m2 = 200g are moving towards each other with velocities

Two lead balls with masses m1 = 100g and m2 = 200g are moving towards each other with velocities v1 = 4m / s and v2 = 5m / s. What kinetic energy will the second ball have after their inelastic collision?

After an inelastic collision, the balls will move as one common ball. Therefore, you need to use the law of conservation of energy:
m1 * v1 + m2 * v2 = V * (m1 + m2);
Let’s convert to the required units of measurement:
m1 = 100 g = 0.1 kg;
m2 = 200 g = 0.2 kg;
Let’s substitute the values into the formula:
0.1 * (-4) + 0.2 * 5 = (0.1 + 0.2) * V;
We get:
– 0.4 + 1 = 0.3 * V;
Find V:
V = 0.6 / 0.3;
V = 2 (m / s) – speed after inelastic collision;
Let’s find the kinetic energy of the second ball:
E = m2 * V² / 2;
E = 0.2 * 2² / 2;
E = 0.4 J.
Answer: E = 0.4 J.