Two light bulbs are connected to the network in parallel. The resistance of the first light bulb is R1 = 360 ohms
| June 23, 2021 | education
Two light bulbs are connected to the network in parallel. The resistance of the first light bulb is R1 = 360 ohms, the second – R2 = 240 ohms. Which of the bulbs absorbs more power and how many times?
When the conductors are connected in parallel, the voltage at their terminals will be the same.
U1 = U2 = U.
Determine the power absorbed by a 360 ohm light bulb.
P1 = U ^ 2 / R1 = U ^ 2/360 W.
Let’s determine the power absorbed by a light bulb with a resistance of 240 ohms.
P2 = U ^ 2 / R1 = U ^ 2/240 W.
Let’s define the power ratio.
P2 / P1 = (U ^ 2/240) / (U ^ 2/360) = 360/240 = 1.5.
Answer: Bulb 2 absorbs 1.5 times more power.
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