Two liquid barometers – mercury and water – are located next to each other.

Two liquid barometers – mercury and water – are located next to each other. In which of them will the liquid column be higher and by how many times?

Under normal conditions, the pressures in the mercury and water barometers will be the same and equal to the value of atmospheric pressure.
Patm. = ρ1 * g * h1 = ρ2 * g * h2, where ρ1 is the density of mercury (ρ1 = 13600 kg / m ^ 3), g is the acceleration of gravity, h1 is the height of the mercury column, ρ2 is the density of water (ρ = 1000 kg / m ^ 3), h2 is the height of the water column.
Then:
ρ1 * g * h1 = ρ2 * g * h2; ρ1 * h1 = ρ2 * h2.
h2 / h1 = ρ1 / ρ2.
h2 / h1 = 13600/1000 = 13.6.
Answer: The liquid column of water will be 13.6 times higher.