Two motorcycles drove out of the two cities towards each other. The speed of the first is 41 2/5 km / h, which is 92%
Two motorcycles drove out of the two cities towards each other. The speed of the first is 41 2/5 km / h, which is 92% of the second. How many hours after the start of movement will the motorcycles meet if the distance between the cities is 91 4/5 km?
Let’s calculate the speed of the second rider. To do this, divide the speed of the first rider – 41.4 kilometers per hour by 0.92:
41.4: 0.92 = 45 kilometers per hour.
The speed of the second rider is 45 kilometers per hour.
Let’s calculate their overall speed. Let’s summarize the speed of the first rider – 41.4 kilometers per hour and the speed of the second rider – 45 kilometers per hour:
41.4 + 45 = 86.4 kilometers per hour.
The total speed is 86.4 kilometers per hour.
91.8: 86.4 = 1 hour 3 minutes 45 seconds.
Answer: Both riders will meet in 1 hour 3 minutes 45 seconds.