Two motorcycles left the two cities at the same time. The speed of one is 98 km / h

Two motorcycles left the two cities at the same time. The speed of one is 98 km / h, the other is 83 km / h. What is the distance between them in 4 hours.

First, we find out how much the speed of the first motorcyclist is greater than the speed of the second. To do this, subtract the second from one speed:

1) 98 km / h – 83 km / h = 15 km / h – the difference in the speed of the motorcyclists.

This means that the first rider goes 15 km / h faster than the second. Therefore, in one hour, the first rider will be 15 km ahead of the second.

Find out how many kilometers in four hours the first motorcyclist is ahead of the second:

2) 15 km / h * 4 h = 60 km.

Bottom line: the distance between motorcyclists in 4 hours will be 60 km.