Two motorcyclists are leaving the two cities at the same time towards each other at a speed of 80 and 60 km / h

| June 1, 2021 | education

Two motorcyclists are leaving the two cities at the same time towards each other at a speed of 80 and 60 km / h, respectively. What path will the first motorcyclist take before meeting the second motorcyclist? Distance between cities 280 km

V1 = 80 km / h.
V2 = 60 km / h.
S = 280 km.
S1 -?
With uniform movement, the distance traveled to the meeting by the first and second motorcyclists is determined by the formula: S1 = V1 * t, S2 = V2 * t, where V1, V2 are the speed of the motorcyclists, t is the travel time before the meeting.
S = S1 + S2.
S = V1 * t + V2 * t.
S = (V1 + V2) * t.
Let us express the time of movement of motorcyclists before the meeting: t = S / (V1 + V2).
t = 280 km / (80 km / h + 60 km / h) = 2 hours.
S1 = 80 km / h * 2 h = 160 km.
Answer: the first motorcyclist will travel S1 = 160 km before the meeting.



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