Two motorcyclists drove out of points A and B at the same time towards each other. The first arrived at B 2.5 hours after their meeting, and the second arrived at A 1.6 hours after the meeting. How many hours did the first motorcyclist travel?
To solve the problem, it is necessary to compose a proportion in which the time before the meeting of each of the motorcyclists will be equal to x, this number is the same for both the first and second motorcyclists, since they left at the same time.
in this case, the ratio of the time before the meeting and the time after the meeting of each motorcyclist will be equal.
x / 2.5 = 1.6 / x.
We multiply the extreme terms of the proportion among ourselves.
x ^ 2 = 4
x = 2.
We find the time of the first motorcyclist on the way.
2.5 + x = 2.5 + 2 = 4.5 hours.
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