# Two motorcyclists were driving towards each other. the speed of one of them is 485 km / h, and it is less than the speed

**Two motorcyclists were driving towards each other. the speed of one of them is 485 km / h, and it is less than the speed of the other by 53 km / h. after 0.6 hours they met. what was the distance between the motorcyclists at the beginning of the journey.**

From the conditions of the problem it follows that the speed of the second motorcyclist is 53 km / h higher than the speed of the first motorcyclist, we calculate it:

485 + 53 = 538 (km / h).

The distance between the motorcyclists at the beginning of the journey is equal to the sum of the distances covered by the motorcyclists before the meeting.

The distance traveled by each of the motorcyclists is equal to the time multiplied by the motorcyclist’s speed.

In this way:

S = S1 + S2 = V1 * t + V2 * t = 458 * 0.6 + 538 * 0.6 = 274.8 +

+ 322.8 = 597.6 (km).

Answer: 597.6 km.