Two opposite vertices of a square have coordinates (2; 1) and (-3; 4). Find the area and perimeter of the square.

Two opposite vertices of a square have coordinates (2; 1) and (-3; 4). Find the area and perimeter of the square. * Write a solution in more detail

Then x1 = 2, y1 = 1, x2 = -3, y2 = 4.

l = √ ((x1 – x2) ^ 2 + (y1 – y2) ^ 2) = √ ((2 – (-3)) ^ 2 + (1 – 4) ^ 2) = √ ((2 + 3) ) ^ 2 + (1 – 4) ^ 2) = √ (5 ^ 2 + (-3) ^ 2) = √ (25 + 3 ^ 2) = √ (25 + 9) = √34,

x = √34 / √2 = √ (34/2) = √17.

S = √17 * √17 = 17.

P = 4 * √17.

Answer: S = 17, P = 4 * √17.



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