Two parallel conductors 2.8 m long each are at a distance of 12 cm from each other and are attracted

| September 10, 2021 | education

Two parallel conductors 2.8 m long each are at a distance of 12 cm from each other and are attracted to each other with a force of 3.4 mN. The current strength of the water one is 58 A. Determine the current strength in the other conductor. How are the electric currents directed in the conductors?

l = 2.8 m.
r = 12 cm = 0.12 m.
F = 3.4 mN = 3.4 * 10 ^ -3 N.
I1 = 58 A.
μ0 = 1.25 * 10 ^ -6 H * / A ^ 2.
I2 -?
The force of interaction of two parallel conductors through which an electric current flows has the form: F = μ0 * I1 * I2 * l / 2 * P * r.
Where μ0 is the magnetic constant, I1, I2 are the currents in the conductors, l is the length of the conductor, P is the number of pi, r is the distance between the conductors.
Let us express the current strength in the second conductor from the formula: I2 = 2 * P * r * F / μ0 * I1 * l.
I2 = 2 * 3.14 * 0.12 m * 3.4 * 10 ^ -3 N / 1.25 * 10 ^ -6 H * / A ^ 2 * 58 A * 2.8 m = 12.6 A …
Since the conductors are attracted, an electric current flows through the conductors in one direction.
Answer: the currents in the conductors have the same direction, the current in the second conductor is I2 = 12.6 A.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.