Two parallel conductors, in which the current strength is the same, are at a distance of 8.7 cm from each other and attract with

Two parallel conductors, in which the current strength is the same, are at a distance of 8.7 cm from each other and attract with a force of 0.025 N. What is the current in the conductors if the length of each of them is 3.2 m.

Let’s write down given (immediately in SI system) The current is => I1 = I2 = I d = 8.7 * 10 ^ (- 2) m F = 2.5 * 10 ^ (- 2) H L = 3.2m
Solution: Let’s use the formula: F = ((МЮ) * I1 * I2 * L) / 2pd, because I1 = I2 = I then the formula can be written as follows: F = ((MU) * I ^ 2 * L) / (2pd); We express I => I = √ (2pdF) / ((МЮ) * L) = √ (2 * 3.14 * 8.7 ^ (- 2) * 2.5 ^ (- 2)) /(4*3.14*10^(-7 ) * 3.2) = 58.3 (A)
Answer: I = 58.3A