Two parallel straight lines AB and CD are given, BC = 16cm, ∠BCD = 30 °. Find the distance between lines AB and CD.
| May 3, 2021 | education
The distance between parallel lines AB and BC is the perpendicular BD between these lines.
ВD parallel to СD, then the triangle ВСD is rectangular, in which, by condition, the angle ВСD = 30, which means that the length of the leg ВD, pushing against this angle, is equal to half the length of the hypotenuse ВС.
ВD = ВС / 2 = 16/2 = 8 cm.
Answer: Between straight AB and CD 8 cm.
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