Two parts were lowered into Water, identical in shape and different in volume, equal or Archimedean forces

Two parts were lowered into Water, identical in shape and different in volume, equal or Archimedean forces acting on them? Why? And the Archimedean force acting on part number one is greater because part number one is wider at the top than at the bottom. B The Archimedean force acting on part number one is greater because in the lower part part number two is wider than the upper part C It is impossible to determine because the density of the liquid is unknown D It is impossible to determine because the volume of the parts is unknown E The Archimedean forces acting on these parts are equal because the shape of the part does not affect on the buoyancy force, but only affects the volume of parts of the parts immersed in the liquid and the density of the liquid.

The buoyancy force of Archimedes is determined by the formula: Farch = ρ * g * V.
Where ρ is the density of the fluid in which the body is immersed, g is the acceleration of gravity, V is the volume of the immersed part of the body in the fluid.
The force of Archimedes depends only on: the density of the fluid ρ in which the body is immersed, g is the acceleration of gravity, the volume of the immersed part of the body in the fluid V.
The force of Archimedes will be greater for a part whose volume will be large.
Answer: it is impossible to determine because the volume of parts is unknown.