Two pedestrians are raised at the same time towards each other. One was moving at a speed of 4 km / h, and the other at 5 km / h.

Two pedestrians are raised at the same time towards each other. One was moving at a speed of 4 km / h, and the other at 5 km / h. What distance did the pedestrians travel if they met through the hour?

V (speed) t (time) S (distance)
1p. 4km / h 3h? km
2p. 5km / h 3h? km
1) 4 + 5 = 9 (km / h) – approach speed
2) 9 × 3 = 27 (km)
Answer: Pedestrians walked 27 kilometers.



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