Two pedestrians left points A and B at the same time towards each other. They met 40 minutes after their exit

Two pedestrians left points A and B at the same time towards each other. They met 40 minutes after their exit, and 32 minutes after the meeting the first one came to B. How many hours after leaving B the second came to A

Taking the distance as 1, we find the travel time of the first pedestrian:

40 + 32 = 72 minutes

Then his speed was:

1: 72 = 1/72 of the way a minute.

The speed of convergence of pedestrians is:

1:40 = 1/40.

Then the speed of the second is:

1/40 – 1/72 = 32/40 * 72 = 1/70.

Its travel time will be:

1: 1/70 = 70 minutes.

Answer: the second pedestrian came to A in 1 hour 10 minutes.