Two pedestrians left points A and B at the same time towards each other. They met 40 minutes after they left

Two pedestrians left points A and B at the same time towards each other. They met 40 minutes after they left, and 32 minutes after the meeting, the first came to B. How many hours after leaving B, the second came to A?

Decision.

1. The first pedestrian was on the way 40 minutes before the meeting and 32 minutes after. His entire journey took 40 + 32 = 72 minutes. Thus, before the meeting, he walked 40/72 all the way.

40/72 = 5/9.

2. If the first pedestrian passed 5/9 of the way before the meeting, then the second during the same time passed 9/9 – 5/9 = 4/9 of the way. In a minute, he covered 4/9/90 = 1/90 of the way.

3. If in a minute the second pedestrian covered 1/90 of the way, then the whole way took him 90 minutes.

Let’s convert minutes to hours. 90 minutes = 1.5 hours

Answer: the second pedestrian arrived at point A 1.5 hours after leaving point B.