Two pedestrians set off towards each other – one from point A to point B, the other from point B to point A.

Two pedestrians set off towards each other – one from point A to point B, the other from point B to point A. Two hours later they met at a distance of 8 km from A and 6 km from B. Having reached their destination, they went back without delay. Where will they meet again?

Since the pedestrians met at a distance of 8 km from A and 6 km from B, the total distance between points A and B is 8 + 6 = 14 km.

Considering that they met in 2 hours after the exit field, the speeds of their movement are 4 km / h and 3 km / h, respectively.

Before the next meeting, pedestrians need to walk another 28 km.

This will happen in 28/7 = 4 hours.

At the time of the meeting, the first pedestrian will walk another 4 * 4 = 16 km.

After passing 6 km, he will reach point B, and, having turned around, will move away from B by 10 km (4 km from A *).



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