Two people carry a metal pipe, resting it on their shoulders. The first person supports the pipe at a distance

Two people carry a metal pipe, resting it on their shoulders. The first person supports the pipe at a distance of 1 m from its end, the second one holds the opposite end of the pipe. How many times is the load on the first person greater than on the second if the pipe length is 2.5 m?

The center of gravity of the pipe is in the center, and the closer to the center the pipe is held, the greater the load will be.
Let’s find at what distance from the edge the center of gravity is, if the length of the entire pipe is 2.5 m:
Ts.t. = l / 2 = 2.5 / 2 = 1.25 m.
Let us find at what distance from the center of gravity the first person holds the pipe:
1.25 – 1 = 0.25 m.
Let us find how many times the load on the first person is greater than on the second, if he holds the pipe by the edge:
1.25 / 0.25 = 5 times.
Answer: the load on the first person will be 5 times more than on the second.