Two pipes fill the pool in 9 hours. Determine how many hours each pipe will fill the pool separately

Two pipes fill the pool in 9 hours. Determine how many hours each pipe will fill the pool separately, if it is known that from one pipe per hour flows out of water 3 times more than from another.

To solve the problem, let’s compose an equation in which we write the filling rate of the first pipe as x.

In this case, the filling rate of the second pipe will be 3 * x, since the second pipe fills the pool three times faster.

In this case, the total volume of the pool will be equal to:

9 * (x + 3 * x) = 36 * x.

Find the time period for which the first pipe will fill the pool.

(36 * x) / x = 36 hours.

We find the time for which the second pipe fills the pool.

(36 * x) / (3 * x) = 12 hours.

Answer: 36 and 12 hours.