Two point charges act on each other with a force of 16n. What will be the interaction force between them

Two point charges act on each other with a force of 16n. What will be the interaction force between them if the value of each charge is reduced by 4 times, without changing the distance between them?

Initial Interaction Strength:

F1 = k * | q1,1 | * | q2,1 | / r² = 16 N, where k is the proportionality coefficient, q1, q2 are the values of the charges, r is the distance between the interacting charges.

Ultimate Interaction Force:

F2 = k * | q1,2 | * | q2,2 | / r², where q1,2 = 0.25q1,1; q2.2 = 0.25q2.1.

F2 / F1 = (k * | q1,2 | * | q2,2 | / r²) / k * | q1,1 | * | q2,1 | / r² = | q1,2 | * | q2,2 | / (| q1,1 | * | q2,1 |) = | 0.25q1,1 | * | 0.25q2.1 | / (| q1,1 | * | q2,1 |) = 0.25 * 0.25 = 0.0625.

F2 = 0.0625 * F1 = 0.0625 * 16 = 1 N.