Two point charges interact with a force of 10H at a distance of 6 * 10 ^ -2m, the value of the charges is

The force with which the charges interact with each other according to the Coulomb’s law:
F = k * q1 * q2 / L², where k is the coefficient 9 * 10 ^ 9, q1 is the charge of the first charge, q2 is the charge of the second charge, L is the distance between them.
For calculations, we assume that the magnitude of our charges is the same, otherwise we can find only the total charge, which means q1 = q2 = q
Then Coulomb’s law:
F = k * q² / L²
Let us express the value of the charge from Coulomb’s law:
q² = F * L² / k
Take the square root of both sides of the equality:
q = √ (F * L² / k)
Substitute the numerical values and determine the charges:
q = √ (F * L² / k) = q = √ (10 * 0.06² / 9 * 10 ^ 9) = 2 * 10 ^ -6 Cl
Answer: the charges are equal to 2 * 10 ^ -6 C or 2 μC.