Two point charges, one of which is four times larger than the other, in air at a distance of 8 cm

| August 19, 2021 | education

Two point charges, one of which is four times larger than the other, in air at a distance of 8 cm from each other interact with a force of 0.049 N. What is the magnitude of each charge?

Data: qz1 (first charge) = 4qz2 (second charge); r is the distance between charges (r = 8 cm = 8 * 10 ^ -2 m); F – force of interaction (F = 0.049 N).

Const: k – coefficient. proportionality (k = 9 * 10 ^ 9 N * m2 / Cl2).

1) Find the first charge: F = k * qz1 * qz2 / r2 = k * qz1 * 4qz1 / r2 = k * 4qz1 ^ 2 / r ^ 2, whence we express: qz1 = √ (F * r ^ 2 / (4 * k)) = √ (0.049 * (8 * 10 ^ -2) ^ 2 / (4 * 9 * 10 ^ 9)) ≈ 9.3 (3) * 10 ^ -8 Cl.

2) Find the second charge: qz2 = 9.3 ^ (3) * 4 = 3.7 ^ (3) * 10 ^ -7 Cl.

Answer: The first and second charges, according to the calculation, are equal to 9.3 ^ (3) * 10 ^ -8 C and 3.7 ^ (3) * 10 ^ -7 C, respectively.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.