Two point identical charges interact with a force of 0.4 mN, being at a distance of 5 cm
| August 11, 2021 | education
Two point identical charges interact with a force of 0.4 mN, being at a distance of 5 cm from each other. What is the magnitude of each charge?
Initial data: F (force of interaction of charges) = 0.4 mN = 0.4 * 10 ^ -3 N; R (distance between charges) = 5 cm = 0.05 m; q = q1 (first charge) = q2 (second charge).
Constants: k (proportionality coefficient) = 9 * 10 ^ 9 N * m ^ 2 / Kl ^ 2.
The magnitude of identical charges can be determined according to Coulomb’s law: F = k * q1 * q2 / R ^ 2 = k * q ^ 2 / R ^ 2, whence q ^ 2 = F * R ^ 2 / k and q = √ (F * R ^ 2 / k).
Calculation: q = √ (0.4 * 10 ^ -3 * 0.05 ^ 2 / (9 * 10 ^ 9)) = 1.05 * 10 ^ -8 Cl.
Answer: The value of each charge is 1.05 * 10 ^ -8 Cl.
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