Two rectangles have the same area. One rectangle is 7.5 cm long and 6.4 cm wide.

| May 1, 2021 | education

Two rectangles have the same area. One rectangle is 7.5 cm long and 6.4 cm wide. The second rectangle is 4 cm wide. Find the perimeter of the second rectangle.

Solution: so, by condition, the area of the first rectangle (S1) is equal to the area of the second rectangle (S2), that is, S1 = S2.
Since the area of a rectangle is calculated by the formula S = a * b, where a is the length of the rectangle, and b is its width.
Therefore, a1 * b1 = a2 * b2.
Substitute the values: 7.5 cm * 6.4 cm = a2 * 4 cm.
Let’s solve the resulting equation: 7.5 cm * 6.4 cm = a2 * 4 cm.
48 cm ^ 2 = a2 * 4 cm.
a2 = 48/4 = 12 cm (the length of the second rectangle is 12 cm).
Next, we find the perimeter of the second rectangle, that is, the sum of the lengths of all its sides:
12 + 4 + 12 + 4 = 16 + 16 = 32 cm.
Answer: 32 cm.



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