# Two rectangles have the same area. The length of the first is 16 cm, the second is 12 cm.

**Two rectangles have the same area. The length of the first is 16 cm, the second is 12 cm. Find the perimeter of the first rectangle ****if the perimeter of the second is 32 cm.**

First, find the width of the second rectangle. We know that the perimeter is 32 and the length is 12 cm, which means:

(32 – 12 – 12) ÷ 2 = 4 cm

That is, the width is 4 cm.

Next, we find the area of the second rectangle. The area is equal to the product of the sides of the rectangle.

S = 4 × 12 = 48 cm2.

Since the areas of the two rectangles are equal, it means that the area of the first is 48 cm2. Find the width of the second rectangle.

48 ÷ 16 = 3 cm

This means that the width of the first rectangle is 3 cm.

We find the perimeter.

P = (16 + 3) × 2 = 38 cm.

Answer: The perimeter is 38 cm.