Two rectangular sections have the same area, the length of the 1st section is 48m and the width is 30.

| May 23, 2021 | education

Two rectangular sections have the same area, the length of the 1st section is 48m and the width is 30. What is the length of the 2nd section if its width is 20% greater than the width of the 1st section.

First, let’s determine the area of the first section.

Area = length x width = 48 * 30 = 1440 (sq. M) The area of the second plot is also 1440 sq. M. by condition.

The width of the second section = 1.2 * width 1 = 1.2 * 30 = 36 (m).

Then the length of the second section = area / width 2 = 1440/36 = 40 (m).

If you do not designate the parameters of the sections, then immediately the solution to the problem:

length 2 = (length 1 * width 1) / (1.2 * width 1) = 48 * 30 / (1.2 * 30) = 48 / 1.2 = 40 (m).

(1.2 * width 1) means that width 2 is 20% larger than width 1.



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