Two rectangular sections have the same area, the length of the first is 45 m, and the width is 30 m.

Two rectangular sections have the same area, the length of the first is 45 m, and the width is 30 m. what is the width of the second section, if its length is 20% less than the length.

Let’s solve this problem using the equation.
1) 45 * 30 = 1 350 square meters – the area of two rectangular plots, so they have the same area;
2) We make the proportion:
45 meters – 100%.
x meters – 20%;
45 / x = 100/20;
x = (45 * 20) / 100;
x = 9 meters – so much the length of the second rectangle is less than the length of the first;
3) 45 – 9 = 36 meters – the length of the second rectangle;
4) 1 350: 36 = 37.5 meters – the width of the second rectangle.
Answer: the width of the second rectangle is 37.5 meters.