Two rectangular sections have the same area, the length of the first is 48 m and the width is 30 m
Two rectangular sections have the same area, the length of the first is 48 m and the width is 30 m than the length of the second section is equal if its width is 6 m more than the sherina of the first section
The solution of the problem:
The area of a rectangle is equal to the product of the length and width of the rectangle. From the condition of the problem, it is known that the areas of the two sections are equal. To answer the question of the problem, you need to know the area of the first section and the width of the second section.
1. Let’s find out what the area of the first section is equal to.
48 * 30 = 1440 square meters.
2. Find out what the width of the second section is equal to.
30 + 6 = 36 meters.
3. Find out what the length of the second section is equal to.
1440/36 = 40 meters.
Answer: The length of the second section is forty meters.