Two resistances of 6 ohms and 8 ohms are connected in series to the network. What is the voltage (V)

Two resistances of 6 ohms and 8 ohms are connected in series to the network. What is the voltage (V) across the first resistance if the voltage across the second is 2 V?

Given:

R1 = 6 Ohm – the value of the first resistance;

R2 = 8 Ohm – the value of the second resistance;

U2 = 2 Volts – voltage across the second resistance.

It is required to determine U1 (Volt) – the voltage across the first resistance.

Determine the strength of the current passing through the second resistance:

I2 = U2 / R2 = 2/8 = 0.25 Amps.

Since, according to the condition of the problem, the resistances are connected in series, then we find that:

I1 = I2 = I = 0.25 Amps.

Then the voltage across the first resistance will be:

U1 = I1 * R1 = 0.25 * 6 = 1.5 Volts.

Answer: the voltage across the first resistance will be 1.5 volts.