Two resistors 50 m and 150 m are connected in series and connected to a 20W voltage source.

Two resistors 50 m and 150 m are connected in series and connected to a 20W voltage source. How much heat will be released in them in 25 seconds?

To find out the heat released on the indicated resistors, we use the formula: Q = U ^ 2 * t / (Rp1 + Rp1), where U is the voltage at the source (U = 20 V); t is the duration of the connection of the indicated resistors to the source (t = 25 s); Rp1 – resistance of one resistor (Rp1 = 50 Ohm); Rp2 is the resistance of another resistor (Rp2 = 150 ohms).
Let’s perform the calculation: Q = U ^ 2 * t / (Rp1 + Rp1) = 20 ^ 2 * 25 / (50 + 150) = 50 J.
Answer: For 25 s, 50 J of heat was released on the indicated resistors.



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