Two resistors are connected in parallel in a circuit, the current strength of which is 2 A.
| May 7, 2021 | education
Two resistors are connected in parallel in a circuit, the current strength of which is 2 A. Determine the current strength in each resistor and the voltage across it, if the resistance of the resistors is 6 and 2 ohms.
I0 = 2 A, R1 = 6 Ohm, R2 = 2 Ohm. Find I1, I2, U1, U2.
The total resistance of a circuit of two parallel-connected conductors: R0 = R1 * R2 / (R1 + R2) = 6 * 2 / (6 + 2) = 1.5 ohms.
For parallel connection of conductors, the voltage drop in the entire circuit is equal to the voltage drop on each conductor: U1 = U2 = U0 = I0 * R0 = 2 * 1.5 = 3 V.
The current in the first resistor is I1 = U1 / R1 = 3/6 = 0.5 A.
The current in the second resistor is I2 = U2 / R2 = 3/2 = 1.5 A.
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