Two resistors are connected in parallel, the resistance of the first 15 ohms, the second 10 ohms.

Two resistors are connected in parallel, the resistance of the first 15 ohms, the second 10 ohms. Another 10 Ohm resistor was connected in series to them. What will be the overall resistance of the circuit?

When calculating the total resistance R of resistors with resistances R₁ and R₂ connected in parallel, the formula is used:

1 / R = 1 / R₁ + 1 / R₂ or R = R₁ ∙ R₂ / (R₁ + R₂).

From the condition of the problem it is known that two resistors are connected in parallel, the resistance of the first R₁ = 15 Ohm, the second R₂ = 10 Ohm, another resistor was connected in series to them, with the resistance R₃ = 10 Ohm. When calculating the total resistance R of resistors connected in series, the formula is used:

Rob = R + R₃. We get:

Rob = R₃ + R₁ ∙ R₂ / (R₁ + R₂).

Substitute the values ​​of the quantities into the calculation formula:

Rob = 10 Ohm + 15 Ohm ∙ 10 Ohm / (15 Ohm + 10 Ohm);

Rob = 16 Ohm.

Answer: The total resistance of the circuit is 16 ohms.