Two resistors are connected in series, and the voltage across them is the same.

Two resistors are connected in series, and the voltage across them is the same. the resistance of the first resistor R1 = 16om, the current strength in it is 2A. what is the voltage across the second resistor?

Given:

I1 = 2A,

R1 = 16 Ohm,

U1 = U2;

Find U2.

Decision:

We use the formula:

Ohm’s law for a section of a chain

U = I * R, where U is the voltage, I is the current, R is the electrical resistance of the conductor.

Since the connection is serial I1 = I2 = Io, according to the condition of the problem U1 = U2, then according to Ohm’s law for a section of the circuit

U1 = I1 * R1 = 2 * 16 = 32 V.

Answer: 32 V