Two resistors of 30 ohms and 16 ohms were connected in series to a current source with an EMF of 64V
| January 13, 2021 | education
Two resistors of 30 ohms and 16 ohms were connected in series to a current source with an EMF of 64V and an internal resistance of 8 ohms. Find the current in the circuit.
The current in the circuit is equal to the ratio of the EMF to the total resistance of the circuit.
The total resistance is equal to the sum of the internal and external resistances.
External resistance in series connection is equal to the sum of the resistances.
R = 30 ohms + 16 ohms = 46 ohms.
I = 64 V / (46 ohms + 8 ohms) = 64 V / 54 ohms = 1.185 A.
This is the approximate amperage, rounded to the nearest thousandth.
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