Two resistors whose resistances are 20 and 30 ohms are included in an electrical circuit with a voltage of 24 V.

Two resistors whose resistances are 20 and 30 ohms are included in an electrical circuit with a voltage of 24 V. What is the current in this circuit when the resistors are connected in series and in parallel?

When resistors are connected in parallel, the voltage across them is equal to the mains voltage. U1 = U2 = 24 V.
According to Ohm’s law, we determine the strength of the current passing through the first resistor.
I1 = U1 / R1 = 24/20 = 1.2 A.
Determine the current passing through the second resistor.
I2 = U2 / R2 = 24/30 = 0.8 A.
The current in the lead wires is equal to the sum of the currents passing through the resistors.
I = I1 + I2 = 1.2 + 0.8 = 2 A.
With a series connection, we determine the total resistance of the circuit.
R = R1 + R2 = 20 + 30 = 50 ohms.
Then I = U / R = 24/50 = 0.48 A.
Answer: With a parallel connection, the current is 2 A, with a serial connection – 0.48 A



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