# Two resistors whose resistances are 20 and 30 ohms are included in an electrical circuit with a voltage of 24 V.

**Two resistors whose resistances are 20 and 30 ohms are included in an electrical circuit with a voltage of 24 V. What is the current in this circuit when the resistors are connected in series and in parallel?**

When resistors are connected in parallel, the voltage across them is equal to the mains voltage. U1 = U2 = 24 V.

According to Ohm’s law, we determine the strength of the current passing through the first resistor.

I1 = U1 / R1 = 24/20 = 1.2 A.

Determine the current passing through the second resistor.

I2 = U2 / R2 = 24/30 = 0.8 A.

The current in the lead wires is equal to the sum of the currents passing through the resistors.

I = I1 + I2 = 1.2 + 0.8 = 2 A.

With a series connection, we determine the total resistance of the circuit.

R = R1 + R2 = 20 + 30 = 50 ohms.

Then I = U / R = 24/50 = 0.48 A.

Answer: With a parallel connection, the current is 2 A, with a serial connection – 0.48 A