Two riders rode towards each other at the same speed and met after 10 hours.

Two riders rode towards each other at the same speed and met after 10 hours. One rode 2 hours more than the other before the meeting and drove 24 km more. What was the distance between them initially?

The first rider rode 10 hours.
Then the second drove 10 + 2 = 12 (h).
Let us denote the distance traveled by 1 rider b km.
Then, according to the condition of problem 2, the rider drove b + 24 km.
The speed of 1 rider can be described as b: 10.
Then the speed of 2 riders (b + 24): 12.
Since the problem indicates that the riders’ speeds are equal, we can write:
b: 10 = (b + 24): 12;
12b = 10 (b + 24);
12b = 10b + 240;
2b = 240;
b = 240: 2 = 120 (km) – 1 rider passed.
b + 24 = 120 + 24 = 144 (km) – 2 riders passed.
The distance between the riders was:
120 + 144 = 264 (km).
Answer: initially there was a distance of 264 km between the riders.