Two ships weighing 50,000 tons each are in the roadstead at a distance of 1 km from each other.

Two ships weighing 50,000 tons each are in the roadstead at a distance of 1 km from each other. What is the force of attraction between them?

Initial data: m = m1 = m2 (ship mass) = 50,000 t, R (distance between ships) = 1 km.
Constants: G (gravitational constant) = 6.67 * 10 ^ -11 m ^ 3 / (kg * s ^ 2).
SI system: m = m1 = m2 = 50,000 t = 50,000,000 kg, R = 1 km = 1000 m.
We calculate the force of gravity between the two ships using the formula:
F = G * m1 * m2 / R ^ 2 = G * m ^ 2 / R ^ 2.
Let’s do the calculation:
F = 6.67 * 10 ^ -11 * 50,000,000 ^ 2 / 1,000 ^ 2 ≈ 0.167 N.
Answer: The force of gravity between the two ships is 0.167 N.