# Two ships weighing 50,000 tons each are in the roadstead at a distance of 1 km from each other.

December 29, 2020 | education

| **Two ships weighing 50,000 tons each are in the roadstead at a distance of 1 km from each other. What is the force of attraction between them?**

Initial data: m = m1 = m2 (ship mass) = 50,000 t, R (distance between ships) = 1 km.

Constants: G (gravitational constant) = 6.67 * 10 ^ -11 m ^ 3 / (kg * s ^ 2).

SI system: m = m1 = m2 = 50,000 t = 50,000,000 kg, R = 1 km = 1000 m.

We calculate the force of gravity between the two ships using the formula:

F = G * m1 * m2 / R ^ 2 = G * m ^ 2 / R ^ 2.

Let’s do the calculation:

F = 6.67 * 10 ^ -11 * 50,000,000 ^ 2 / 1,000 ^ 2 ≈ 0.167 N.

Answer: The force of gravity between the two ships is 0.167 N.

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