Two shooters independently of each other make one shot at the target. The hit probability for the first shooter

Two shooters independently of each other make one shot at the target. The hit probability for the first shooter is 0.8; for the second – 0.6. Find the probability that only one shooter will hit the target.

The probability of hitting the target for the first shooter is 0.8, then the probability of a miss 1 – 0.8 = 0.2.

The probability of hitting for the second is 0.6, then the probability of a miss 1 – 0.6 = 0.4.

The probability of the event “that only one shooter will hit the target” is the sum of two inconsistent events: the first hit the target, and the second missed, or the first missed, and the second hit the target.

P (A) = 0.8 * 0.4 + 0.2 * 0.6 = 0.32 + 0.12 = 0.44.

Answer: 0.44.